F(3)=(-2x^2)+3x-6

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Solution for F(3)=(-2x^2)+3x-6 equation: 



(3)=(-2F^2)+3F-6

We move all terms to the left:

(3)-((-2F^2)+3F-6)=0



We calculate terms in parentheses: -((-2F^2)+3F-6), so:

(-2F^2)+3F-6

We get rid of parentheses

-2F^2+3F-6

Back to the equation:

-(-2F^2+3F-6)



We get rid of parentheses

2F^2-3F+6+3=0

We add all the numbers together, and all the variables

2F^2-3F+9=0

a = 2; b = -3; c = +9;
Δ = b2-4ac
Δ = -32-4·2·9
Δ = -63
Delta is less than zero, so there is no solution for the equation

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